3.130 \(\int (a+b x)^m (c+d x)^{-4-m} (e+f x) (g+h x) \, dx\)

Optimal. Leaf size=362 \[ \frac{(a+b x)^{m+1} (c+d x)^{-m-2} \left (a^2 d^2 f h \left (m^2+5 m+6\right )-a b d (m+3) (2 c f h (m+1)+d (e h+f g))+b^2 \left (c^2 f h \left (m^2+3 m+2\right )+c d (m+1) (e h+f g)+2 d^2 e g\right )\right )}{b d^2 (m+2) (m+3) (b c-a d)^2}+\frac{(a+b x)^{m+1} (c+d x)^{-m-1} \left (a^2 d^2 f h \left (m^2+5 m+6\right )-a b d (m+3) (2 c f h (m+1)+d (e h+f g))+b^2 \left (c^2 f h \left (m^2+3 m+2\right )+c d (m+1) (e h+f g)+2 d^2 e g\right )\right )}{d^2 (m+1) (m+2) (m+3) (b c-a d)^3}+\frac{(a+b x)^{m+1} (c+d x)^{-m-3} \left (-d f h (m+3) x (b c-a d)+a c d f h (m+3)+b \left (c^2 (-f) h (m+2)-c d (e h+f g)+d^2 e g\right )\right )}{b d^2 (m+3) (b c-a d)} \]

[Out]

((a^2*d^2*f*h*(6 + 5*m + m^2) - a*b*d*(3 + m)*(d*(f*g + e*h) + 2*c*f*h*(1 + m)) + b^2*(2*d^2*e*g + c*d*(f*g +
e*h)*(1 + m) + c^2*f*h*(2 + 3*m + m^2)))*(a + b*x)^(1 + m)*(c + d*x)^(-2 - m))/(b*d^2*(b*c - a*d)^2*(2 + m)*(3
+ m)) + ((a^2*d^2*f*h*(6 + 5*m + m^2) - a*b*d*(3 + m)*(d*(f*g + e*h) + 2*c*f*h*(1 + m)) + b^2*(2*d^2*e*g + c*
d*(f*g + e*h)*(1 + m) + c^2*f*h*(2 + 3*m + m^2)))*(a + b*x)^(1 + m)*(c + d*x)^(-1 - m))/(d^2*(b*c - a*d)^3*(1
+ m)*(2 + m)*(3 + m)) + ((a + b*x)^(1 + m)*(c + d*x)^(-3 - m)*(a*c*d*f*h*(3 + m) + b*(d^2*e*g - c*d*(f*g + e*h
) - c^2*f*h*(2 + m)) - d*(b*c - a*d)*f*h*(3 + m)*x))/(b*d^2*(b*c - a*d)*(3 + m))

________________________________________________________________________________________

Rubi [A]  time = 0.361866, antiderivative size = 362, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.103, Rules used = {146, 45, 37} \[ \frac{(a+b x)^{m+1} (c+d x)^{-m-2} \left (a^2 d^2 f h \left (m^2+5 m+6\right )-a b d (m+3) (2 c f h (m+1)+d (e h+f g))+b^2 \left (c^2 f h \left (m^2+3 m+2\right )+c d (m+1) (e h+f g)+2 d^2 e g\right )\right )}{b d^2 (m+2) (m+3) (b c-a d)^2}+\frac{(a+b x)^{m+1} (c+d x)^{-m-1} \left (a^2 d^2 f h \left (m^2+5 m+6\right )-a b d (m+3) (2 c f h (m+1)+d (e h+f g))+b^2 \left (c^2 f h \left (m^2+3 m+2\right )+c d (m+1) (e h+f g)+2 d^2 e g\right )\right )}{d^2 (m+1) (m+2) (m+3) (b c-a d)^3}+\frac{(a+b x)^{m+1} (c+d x)^{-m-3} \left (-d f h (m+3) x (b c-a d)+a c d f h (m+3)+b \left (c^2 (-f) h (m+2)-c d (e h+f g)+d^2 e g\right )\right )}{b d^2 (m+3) (b c-a d)} \]

Antiderivative was successfully verified.

[In]

Int[(a + b*x)^m*(c + d*x)^(-4 - m)*(e + f*x)*(g + h*x),x]

[Out]

((a^2*d^2*f*h*(6 + 5*m + m^2) - a*b*d*(3 + m)*(d*(f*g + e*h) + 2*c*f*h*(1 + m)) + b^2*(2*d^2*e*g + c*d*(f*g +
e*h)*(1 + m) + c^2*f*h*(2 + 3*m + m^2)))*(a + b*x)^(1 + m)*(c + d*x)^(-2 - m))/(b*d^2*(b*c - a*d)^2*(2 + m)*(3
+ m)) + ((a^2*d^2*f*h*(6 + 5*m + m^2) - a*b*d*(3 + m)*(d*(f*g + e*h) + 2*c*f*h*(1 + m)) + b^2*(2*d^2*e*g + c*
d*(f*g + e*h)*(1 + m) + c^2*f*h*(2 + 3*m + m^2)))*(a + b*x)^(1 + m)*(c + d*x)^(-1 - m))/(d^2*(b*c - a*d)^3*(1
+ m)*(2 + m)*(3 + m)) + ((a + b*x)^(1 + m)*(c + d*x)^(-3 - m)*(a*c*d*f*h*(3 + m) + b*(d^2*e*g - c*d*(f*g + e*h
) - c^2*f*h*(2 + m)) - d*(b*c - a*d)*f*h*(3 + m)*x))/(b*d^2*(b*c - a*d)*(3 + m))

Rule 146

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_) + (f_.)*(x_))*((g_.) + (h_.)*(x_)), x_Symbol] :
> Simp[((a^2*d*f*h*(n + 2) + b^2*d*e*g*(m + n + 3) + a*b*(c*f*h*(m + 1) - d*(f*g + e*h)*(m + n + 3)) + b*f*h*(
b*c - a*d)*(m + 1)*x)*(a + b*x)^(m + 1)*(c + d*x)^(n + 1))/(b^2*d*(b*c - a*d)*(m + 1)*(m + n + 3)), x] - Dist[
(a^2*d^2*f*h*(n + 1)*(n + 2) + a*b*d*(n + 1)*(2*c*f*h*(m + 1) - d*(f*g + e*h)*(m + n + 3)) + b^2*(c^2*f*h*(m +
1)*(m + 2) - c*d*(f*g + e*h)*(m + 1)*(m + n + 3) + d^2*e*g*(m + n + 2)*(m + n + 3)))/(b^2*d*(b*c - a*d)*(m +
1)*(m + n + 3)), Int[(a + b*x)^(m + 1)*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d, e, f, g, h, m, n}, x] && ((Ge
Q[m, -2] && LtQ[m, -1]) || SumSimplerQ[m, 1]) && NeQ[m, -1] && NeQ[m + n + 3, 0]

Rule 45

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n + 1
))/((b*c - a*d)*(m + 1)), x] - Dist[(d*Simplify[m + n + 2])/((b*c - a*d)*(m + 1)), Int[(a + b*x)^Simplify[m +
1]*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && ILtQ[Simplify[m + n + 2], 0] &&
NeQ[m, -1] &&  !(LtQ[m, -1] && LtQ[n, -1] && (EqQ[a, 0] || (NeQ[c, 0] && LtQ[m - n, 0] && IntegerQ[n]))) && (
SumSimplerQ[m, 1] ||  !SumSimplerQ[n, 1])

Rule 37

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n +
1))/((b*c - a*d)*(m + 1)), x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && EqQ[m + n + 2, 0] && NeQ
[m, -1]

Rubi steps

\begin{align*} \int (a+b x)^m (c+d x)^{-4-m} (e+f x) (g+h x) \, dx &=\frac{(a+b x)^{1+m} (c+d x)^{-3-m} \left (a c d f h (3+m)+b \left (d^2 e g-c d (f g+e h)-c^2 f h (2+m)\right )-d (b c-a d) f h (3+m) x\right )}{b d^2 (b c-a d) (3+m)}+\frac{\left (a^2 d^2 f h \left (6+5 m+m^2\right )-a b d (3+m) (d (f g+e h)+2 c f h (1+m))+b^2 \left (2 d^2 e g+c d (f g+e h) (1+m)+c^2 f h \left (2+3 m+m^2\right )\right )\right ) \int (a+b x)^m (c+d x)^{-3-m} \, dx}{b d^2 (b c-a d) (3+m)}\\ &=\frac{\left (a^2 d^2 f h \left (6+5 m+m^2\right )-a b d (3+m) (d (f g+e h)+2 c f h (1+m))+b^2 \left (2 d^2 e g+c d (f g+e h) (1+m)+c^2 f h \left (2+3 m+m^2\right )\right )\right ) (a+b x)^{1+m} (c+d x)^{-2-m}}{b d^2 (b c-a d)^2 (2+m) (3+m)}+\frac{(a+b x)^{1+m} (c+d x)^{-3-m} \left (a c d f h (3+m)+b \left (d^2 e g-c d (f g+e h)-c^2 f h (2+m)\right )-d (b c-a d) f h (3+m) x\right )}{b d^2 (b c-a d) (3+m)}+\frac{\left (a^2 d^2 f h \left (6+5 m+m^2\right )-a b d (3+m) (d (f g+e h)+2 c f h (1+m))+b^2 \left (2 d^2 e g+c d (f g+e h) (1+m)+c^2 f h \left (2+3 m+m^2\right )\right )\right ) \int (a+b x)^m (c+d x)^{-2-m} \, dx}{d^2 (b c-a d)^2 (2+m) (3+m)}\\ &=\frac{\left (a^2 d^2 f h \left (6+5 m+m^2\right )-a b d (3+m) (d (f g+e h)+2 c f h (1+m))+b^2 \left (2 d^2 e g+c d (f g+e h) (1+m)+c^2 f h \left (2+3 m+m^2\right )\right )\right ) (a+b x)^{1+m} (c+d x)^{-2-m}}{b d^2 (b c-a d)^2 (2+m) (3+m)}+\frac{\left (a^2 d^2 f h \left (6+5 m+m^2\right )-a b d (3+m) (d (f g+e h)+2 c f h (1+m))+b^2 \left (2 d^2 e g+c d (f g+e h) (1+m)+c^2 f h \left (2+3 m+m^2\right )\right )\right ) (a+b x)^{1+m} (c+d x)^{-1-m}}{d^2 (b c-a d)^3 (1+m) (2+m) (3+m)}+\frac{(a+b x)^{1+m} (c+d x)^{-3-m} \left (a c d f h (3+m)+b \left (d^2 e g-c d (f g+e h)-c^2 f h (2+m)\right )-d (b c-a d) f h (3+m) x\right )}{b d^2 (b c-a d) (3+m)}\\ \end{align*}

Mathematica [A]  time = 0.54954, size = 220, normalized size = 0.61 \[ \frac{(a+b x)^{m+1} (c+d x)^{-m-3} \left (\frac{(c+d x) (-a d (m+1)+b c (m+2)+b d x) \left (a^2 d^2 f h \left (m^2+5 m+6\right )-a b d (m+3) (2 c f h (m+1)+d (e h+f g))+b^2 \left (c^2 f h \left (m^2+3 m+2\right )+c d (m+1) (e h+f g)+2 d^2 e g\right )\right )}{(m+1) (m+2) (b c-a d)^2}+a d f h (m+3) (c+d x)+b \left (c^2 (-f) h (m+2)-c d (e h+f (g+h (m+3) x))+d^2 e g\right )\right )}{b d^2 (m+3) (b c-a d)} \]

Antiderivative was successfully verified.

[In]

Integrate[(a + b*x)^m*(c + d*x)^(-4 - m)*(e + f*x)*(g + h*x),x]

[Out]

((a + b*x)^(1 + m)*(c + d*x)^(-3 - m)*(a*d*f*h*(3 + m)*(c + d*x) + ((a^2*d^2*f*h*(6 + 5*m + m^2) - a*b*d*(3 +
m)*(d*(f*g + e*h) + 2*c*f*h*(1 + m)) + b^2*(2*d^2*e*g + c*d*(f*g + e*h)*(1 + m) + c^2*f*h*(2 + 3*m + m^2)))*(c
+ d*x)*(-(a*d*(1 + m)) + b*c*(2 + m) + b*d*x))/((b*c - a*d)^2*(1 + m)*(2 + m)) + b*(d^2*e*g - c^2*f*h*(2 + m)
- c*d*(e*h + f*(g + h*(3 + m)*x)))))/(b*d^2*(b*c - a*d)*(3 + m))

________________________________________________________________________________________

Maple [B]  time = 0.008, size = 894, normalized size = 2.5 \begin{align*} -{\frac{ \left ( bx+a \right ) ^{1+m} \left ( dx+c \right ) ^{-3-m} \left ({a}^{2}{d}^{2}fh{m}^{2}{x}^{2}-2\,abcdfh{m}^{2}{x}^{2}+{b}^{2}{c}^{2}fh{m}^{2}{x}^{2}+{a}^{2}{d}^{2}eh{m}^{2}x+{a}^{2}{d}^{2}fg{m}^{2}x+5\,{a}^{2}{d}^{2}fhm{x}^{2}-2\,abcdeh{m}^{2}x-2\,abcdfg{m}^{2}x-8\,abcdfhm{x}^{2}-ab{d}^{2}ehm{x}^{2}-ab{d}^{2}fgm{x}^{2}+{b}^{2}{c}^{2}eh{m}^{2}x+{b}^{2}{c}^{2}fg{m}^{2}x+3\,{b}^{2}{c}^{2}fhm{x}^{2}+{b}^{2}cdehm{x}^{2}+{b}^{2}cdfgm{x}^{2}+2\,{a}^{2}cdfhmx+{a}^{2}{d}^{2}eg{m}^{2}+4\,{a}^{2}{d}^{2}ehmx+4\,{a}^{2}{d}^{2}fgmx+6\,{a}^{2}{d}^{2}fh{x}^{2}-2\,ab{c}^{2}fhmx-2\,abcdeg{m}^{2}-8\,abcdehmx-8\,abcdfgmx-6\,abcdfh{x}^{2}-2\,ab{d}^{2}egmx-3\,ab{d}^{2}eh{x}^{2}-3\,ab{d}^{2}fg{x}^{2}+{b}^{2}{c}^{2}eg{m}^{2}+4\,{b}^{2}{c}^{2}ehmx+4\,{b}^{2}{c}^{2}fgmx+2\,{b}^{2}{c}^{2}fh{x}^{2}+2\,{b}^{2}cdegmx+{b}^{2}cdeh{x}^{2}+{b}^{2}cdfg{x}^{2}+2\,{b}^{2}{d}^{2}eg{x}^{2}+{a}^{2}cdehm+{a}^{2}cdfgm+6\,{a}^{2}cdfhx+3\,{a}^{2}{d}^{2}egm+3\,{a}^{2}{d}^{2}ehx+3\,{a}^{2}{d}^{2}fgx-ab{c}^{2}ehm-ab{c}^{2}fgm-2\,ab{c}^{2}fhx-8\,abcdegm-10\,abcdehx-10\,abcdfgx-2\,ab{d}^{2}egx+5\,{b}^{2}{c}^{2}egm+3\,{b}^{2}{c}^{2}ehx+3\,{b}^{2}{c}^{2}fgx+6\,{b}^{2}cdegx+2\,{a}^{2}{c}^{2}fh+{a}^{2}cdeh+{a}^{2}cdfg+2\,{a}^{2}{d}^{2}eg-3\,ab{c}^{2}eh-3\,ab{c}^{2}fg-6\,abcdeg+6\,{b}^{2}{c}^{2}eg \right ) }{{a}^{3}{d}^{3}{m}^{3}-3\,{a}^{2}bc{d}^{2}{m}^{3}+3\,a{b}^{2}{c}^{2}d{m}^{3}-{b}^{3}{c}^{3}{m}^{3}+6\,{a}^{3}{d}^{3}{m}^{2}-18\,{a}^{2}bc{d}^{2}{m}^{2}+18\,a{b}^{2}{c}^{2}d{m}^{2}-6\,{b}^{3}{c}^{3}{m}^{2}+11\,{a}^{3}{d}^{3}m-33\,{a}^{2}bc{d}^{2}m+33\,a{b}^{2}{c}^{2}dm-11\,{b}^{3}{c}^{3}m+6\,{a}^{3}{d}^{3}-18\,{a}^{2}bc{d}^{2}+18\,a{b}^{2}{c}^{2}d-6\,{b}^{3}{c}^{3}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x+a)^m*(d*x+c)^(-4-m)*(f*x+e)*(h*x+g),x)

[Out]

-(b*x+a)^(1+m)*(d*x+c)^(-3-m)*(a^2*d^2*f*h*m^2*x^2-2*a*b*c*d*f*h*m^2*x^2+b^2*c^2*f*h*m^2*x^2+a^2*d^2*e*h*m^2*x
+a^2*d^2*f*g*m^2*x+5*a^2*d^2*f*h*m*x^2-2*a*b*c*d*e*h*m^2*x-2*a*b*c*d*f*g*m^2*x-8*a*b*c*d*f*h*m*x^2-a*b*d^2*e*h
*m*x^2-a*b*d^2*f*g*m*x^2+b^2*c^2*e*h*m^2*x+b^2*c^2*f*g*m^2*x+3*b^2*c^2*f*h*m*x^2+b^2*c*d*e*h*m*x^2+b^2*c*d*f*g
*m*x^2+2*a^2*c*d*f*h*m*x+a^2*d^2*e*g*m^2+4*a^2*d^2*e*h*m*x+4*a^2*d^2*f*g*m*x+6*a^2*d^2*f*h*x^2-2*a*b*c^2*f*h*m
*x-2*a*b*c*d*e*g*m^2-8*a*b*c*d*e*h*m*x-8*a*b*c*d*f*g*m*x-6*a*b*c*d*f*h*x^2-2*a*b*d^2*e*g*m*x-3*a*b*d^2*e*h*x^2
-3*a*b*d^2*f*g*x^2+b^2*c^2*e*g*m^2+4*b^2*c^2*e*h*m*x+4*b^2*c^2*f*g*m*x+2*b^2*c^2*f*h*x^2+2*b^2*c*d*e*g*m*x+b^2
*c*d*e*h*x^2+b^2*c*d*f*g*x^2+2*b^2*d^2*e*g*x^2+a^2*c*d*e*h*m+a^2*c*d*f*g*m+6*a^2*c*d*f*h*x+3*a^2*d^2*e*g*m+3*a
^2*d^2*e*h*x+3*a^2*d^2*f*g*x-a*b*c^2*e*h*m-a*b*c^2*f*g*m-2*a*b*c^2*f*h*x-8*a*b*c*d*e*g*m-10*a*b*c*d*e*h*x-10*a
*b*c*d*f*g*x-2*a*b*d^2*e*g*x+5*b^2*c^2*e*g*m+3*b^2*c^2*e*h*x+3*b^2*c^2*f*g*x+6*b^2*c*d*e*g*x+2*a^2*c^2*f*h+a^2
*c*d*e*h+a^2*c*d*f*g+2*a^2*d^2*e*g-3*a*b*c^2*e*h-3*a*b*c^2*f*g-6*a*b*c*d*e*g+6*b^2*c^2*e*g)/(a^3*d^3*m^3-3*a^2
*b*c*d^2*m^3+3*a*b^2*c^2*d*m^3-b^3*c^3*m^3+6*a^3*d^3*m^2-18*a^2*b*c*d^2*m^2+18*a*b^2*c^2*d*m^2-6*b^3*c^3*m^2+1
1*a^3*d^3*m-33*a^2*b*c*d^2*m+33*a*b^2*c^2*d*m-11*b^3*c^3*m+6*a^3*d^3-18*a^2*b*c*d^2+18*a*b^2*c^2*d-6*b^3*c^3)

________________________________________________________________________________________

Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (f x + e\right )}{\left (h x + g\right )}{\left (b x + a\right )}^{m}{\left (d x + c\right )}^{-m - 4}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^m*(d*x+c)^(-4-m)*(f*x+e)*(h*x+g),x, algorithm="maxima")

[Out]

integrate((f*x + e)*(h*x + g)*(b*x + a)^m*(d*x + c)^(-m - 4), x)

________________________________________________________________________________________

Fricas [B]  time = 1.4598, size = 3309, normalized size = 9.14 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^m*(d*x+c)^(-4-m)*(f*x+e)*(h*x+g),x, algorithm="fricas")

[Out]

((a*b^2*c^3 - 2*a^2*b*c^2*d + a^3*c*d^2)*e*g*m^2 + ((b^3*c^2*d - 2*a*b^2*c*d^2 + a^2*b*d^3)*f*h*m^2 + (2*b^3*d
^3*e + (b^3*c*d^2 - 3*a*b^2*d^3)*f)*g + ((b^3*c*d^2 - 3*a*b^2*d^3)*e + 2*(b^3*c^2*d - 3*a*b^2*c*d^2 + 3*a^2*b*
d^3)*f)*h + ((b^3*c*d^2 - a*b^2*d^3)*f*g + ((b^3*c*d^2 - a*b^2*d^3)*e + (3*b^3*c^2*d - 8*a*b^2*c*d^2 + 5*a^2*b
*d^3)*f)*h)*m)*x^4 + (((b^3*c^2*d - 2*a*b^2*c*d^2 + a^2*b*d^3)*f*g + ((b^3*c^2*d - 2*a*b^2*c*d^2 + a^2*b*d^3)*
e + (b^3*c^3 - a*b^2*c^2*d - a^2*b*c*d^2 + a^3*d^3)*f)*h)*m^2 + 4*(2*b^3*c*d^2*e + (b^3*c^2*d - 3*a*b^2*c*d^2)
*f)*g + 2*(2*(b^3*c^2*d - 3*a*b^2*c*d^2)*e + (b^3*c^3 - 3*a*b^2*c^2*d + 3*a^2*b*c*d^2 + 3*a^3*d^3)*f)*h + ((2*
(b^3*c*d^2 - a*b^2*d^3)*e + (5*b^3*c^2*d - 8*a*b^2*c*d^2 + 3*a^2*b*d^3)*f)*g + ((5*b^3*c^2*d - 8*a*b^2*c*d^2 +
3*a^2*b*d^3)*e + (3*b^3*c^3 - 7*a*b^2*c^2*d - a^2*b*c*d^2 + 5*a^3*d^3)*f)*h)*m)*x^3 + ((((b^3*c^2*d - 2*a*b^2
*c*d^2 + a^2*b*d^3)*e + (b^3*c^3 - a*b^2*c^2*d - a^2*b*c*d^2 + a^3*d^3)*f)*g + ((b^3*c^3 - a*b^2*c^2*d - a^2*b
*c*d^2 + a^3*d^3)*e + (a*b^2*c^3 - 2*a^2*b*c^2*d + a^3*c*d^2)*f)*h)*m^2 + 3*(4*b^3*c^2*d*e + (b^3*c^3 - 3*a*b^
2*c^2*d - 3*a^2*b*c*d^2 + a^3*d^3)*f)*g + 3*(4*a^3*c*d^2*f + (b^3*c^3 - 3*a*b^2*c^2*d - 3*a^2*b*c*d^2 + a^3*d^
3)*e)*h + (((7*b^3*c^2*d - 8*a*b^2*c*d^2 + a^2*b*d^3)*e + 4*(b^3*c^3 - a*b^2*c^2*d - a^2*b*c*d^2 + a^3*d^3)*f)
*g + (4*(b^3*c^3 - a*b^2*c^2*d - a^2*b*c*d^2 + a^3*d^3)*e + (a*b^2*c^3 - 8*a^2*b*c^2*d + 7*a^3*c*d^2)*f)*h)*m)
*x^2 + (2*(3*a*b^2*c^3 - 3*a^2*b*c^2*d + a^3*c*d^2)*e - (3*a^2*b*c^3 - a^3*c^2*d)*f)*g + (2*a^3*c^3*f - (3*a^2
*b*c^3 - a^3*c^2*d)*e)*h - ((a^2*b*c^3 - a^3*c^2*d)*e*h - ((5*a*b^2*c^3 - 8*a^2*b*c^2*d + 3*a^3*c*d^2)*e - (a^
2*b*c^3 - a^3*c^2*d)*f)*g)*m + (((a*b^2*c^3 - 2*a^2*b*c^2*d + a^3*c*d^2)*e*h + ((b^3*c^3 - a*b^2*c^2*d - a^2*b
*c*d^2 + a^3*d^3)*e + (a*b^2*c^3 - 2*a^2*b*c^2*d + a^3*c*d^2)*f)*g)*m^2 + 2*((3*b^3*c^3 + 3*a*b^2*c^2*d - 3*a^
2*b*c*d^2 + a^3*d^3)*e - 2*(3*a^2*b*c^2*d - a^3*c*d^2)*f)*g + 4*(2*a^3*c^2*d*f - (3*a^2*b*c^2*d - a^3*c*d^2)*e
)*h + (((5*b^3*c^3 - a*b^2*c^2*d - 7*a^2*b*c*d^2 + 3*a^3*d^3)*e + (3*a*b^2*c^3 - 8*a^2*b*c^2*d + 5*a^3*c*d^2)*
f)*g + ((3*a*b^2*c^3 - 8*a^2*b*c^2*d + 5*a^3*c*d^2)*e - 2*(a^2*b*c^3 - a^3*c^2*d)*f)*h)*m)*x)*(b*x + a)^m*(d*x
+ c)^(-m - 4)/(6*b^3*c^3 - 18*a*b^2*c^2*d + 18*a^2*b*c*d^2 - 6*a^3*d^3 + (b^3*c^3 - 3*a*b^2*c^2*d + 3*a^2*b*c
*d^2 - a^3*d^3)*m^3 + 6*(b^3*c^3 - 3*a*b^2*c^2*d + 3*a^2*b*c*d^2 - a^3*d^3)*m^2 + 11*(b^3*c^3 - 3*a*b^2*c^2*d
+ 3*a^2*b*c*d^2 - a^3*d^3)*m)

________________________________________________________________________________________

Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)**m*(d*x+c)**(-4-m)*(f*x+e)*(h*x+g),x)

[Out]

Timed out

________________________________________________________________________________________

Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (f x + e\right )}{\left (h x + g\right )}{\left (b x + a\right )}^{m}{\left (d x + c\right )}^{-m - 4}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^m*(d*x+c)^(-4-m)*(f*x+e)*(h*x+g),x, algorithm="giac")

[Out]

integrate((f*x + e)*(h*x + g)*(b*x + a)^m*(d*x + c)^(-m - 4), x)